(x-2/3)^2-(y-1/4)^2=49

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Solution for (x-2/3)^2-(y-1/4)^2=49 equation: 


x in (-oo:+oo)

t_1 = -(y-1/4)^2-49

(x-2/3)^2+t_1 = 0

(x-2/3)^2+t_1 = 0

t_1+x^2-4/3*x+4/9 = 0

t_1+x^2-4/3*x+4/9 = 0

t_1+x^2-4/3*x+4/9 = 0

DELTA = (-4/3)^2-(1*4*(t_1+4/9))

DELTA = 16/9-4*(t_1+4/9)

16/9-4*(t_1+4/9) = 0

(-4*9*(t_1+4/9))/9+16/9 = 0

16-4*9*(t_1+4/9) = 0

-36*t_1 = 0

(-36*t_1)/9 = 0

(-36*t_1)/9 = 0 // * 9

-36*t_1 = 0

-36*t_1 = 0 // : -36

t_1 = 0

DELTA = 0  <=>  t_4 = 0

x = 4/3/(1*2) i t_1 = 0

x = 2/3 i t_1 = 0

( x = ((16/9-4*(t_1+4/9))^(1/2)+4/3)/(1*2) or x = (4/3-(16/9-4*(t_1+4/9))^(1/2))/(1*2) ) i t_1 > 0

( x = ((16/9-4*(t_1+4/9))^(1/2)+4/3)/2 or x = (4/3-(16/9-4*(t_1+4/9))^(1/2))/2 ) i t_1 > 0

t_1+0 > 0

t_1 > 0

t_1+0 > 0 // - 0

t_1 > 0

x in { 2/3, ((16/9-4*(4/9-(y-1/4)^2-49))^(1/2)+4/3)/2, (4/3-(16/9-4*(4/9-(y-1/4)^2-49))^(1/2))/2 }

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